Base | Representation |
---|---|
bin | 11001100100000110110001… |
… | …111001011010011111011011 |
3 | 112202002102112100000022211212 |
4 | 121210012301321122133123 |
5 | 104214042414420302324 |
6 | 1035042412223013335 |
7 | 32452653166406105 |
oct | 3144066171323733 |
9 | 482072470008755 |
10 | 112432343525339 |
11 | 3290831a8a6702 |
12 | 1073a18443a24b |
13 | 4a9742ac10426 |
14 | 1da9a7c35a575 |
15 | cee95383070e |
hex | 6641b1e5a7db |
112432343525339 has 2 divisors, whose sum is σ = 112432343525340. Its totient is φ = 112432343525338.
The previous prime is 112432343525323. The next prime is 112432343525377. The reversal of 112432343525339 is 933525343234211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112432343525339 - 24 = 112432343525323 is a prime.
It is a super-3 number, since 3×1124323435253393 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (112432343525239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56216171762669 + 56216171762670.
It is an arithmetic number, because the mean of its divisors is an integer number (56216171762670).
Almost surely, 2112432343525339 is an apocalyptic number.
112432343525339 is a deficient number, since it is larger than the sum of its proper divisors (1).
112432343525339 is an equidigital number, since it uses as much as digits as its factorization.
112432343525339 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6998400, while the sum is 50.
The spelling of 112432343525339 in words is "one hundred twelve trillion, four hundred thirty-two billion, three hundred forty-three million, five hundred twenty-five thousand, three hundred thirty-nine".
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