Base | Representation |
---|---|
bin | 10100111100010011… |
… | …10111011100010011 |
3 | 1002000120021220001021 |
4 | 22132021313130103 |
5 | 141011242233412 |
6 | 5055355220311 |
7 | 545422436554 |
oct | 123611673423 |
9 | 32016256037 |
10 | 11243321107 |
11 | 484a61a617 |
12 | 2219447697 |
13 | 10a246c035 |
14 | 78932c32b |
15 | 45c104607 |
hex | 29e277713 |
11243321107 has 2 divisors, whose sum is σ = 11243321108. Its totient is φ = 11243321106.
The previous prime is 11243321077. The next prime is 11243321147. The reversal of 11243321107 is 70112334211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11243321107 is a prime.
It is a super-2 number, since 2×112433211072 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11243321147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621660553 + 5621660554.
It is an arithmetic number, because the mean of its divisors is an integer number (5621660554).
Almost surely, 211243321107 is an apocalyptic number.
11243321107 is a deficient number, since it is larger than the sum of its proper divisors (1).
11243321107 is an equidigital number, since it uses as much as digits as its factorization.
11243321107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 11243321107 its reverse (70112334211), we get a palindrome (81355655318).
The spelling of 11243321107 in words is "eleven billion, two hundred forty-three million, three hundred twenty-one thousand, one hundred seven".
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