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112441120440433 is a prime number
BaseRepresentation
bin11001100100001110111101…
…000010101100000001110001
3112202010021012000022210220021
4121210032331002230001301
5104214213403313043213
61035050423154443441
732453413533064621
oct3144167502540161
9482107160283807
10112441120440433
1132911014177944
121073ba13893581
134a981c93b2b05
141daa271ca0881
15ceecb9142d8d
hex6643bd0ac071

112441120440433 has 2 divisors, whose sum is σ = 112441120440434. Its totient is φ = 112441120440432.

The previous prime is 112441120440409. The next prime is 112441120440463. The reversal of 112441120440433 is 334044021144211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68500237061169 + 43940883379264 = 8276487^2 + 6628792^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112441120440433 is a prime.

It is not a weakly prime, because it can be changed into another prime (112441120440463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56220560220216 + 56220560220217.

It is an arithmetic number, because the mean of its divisors is an integer number (56220560220217).

Almost surely, 2112441120440433 is an apocalyptic number.

It is an amenable number.

112441120440433 is a deficient number, since it is larger than the sum of its proper divisors (1).

112441120440433 is an equidigital number, since it uses as much as digits as its factorization.

112441120440433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36864, while the sum is 34.

Adding to 112441120440433 its reverse (334044021144211), we get a palindrome (446485141584644).

The spelling of 112441120440433 in words is "one hundred twelve trillion, four hundred forty-one billion, one hundred twenty million, four hundred forty thousand, four hundred thirty-three".