Base | Representation |
---|---|
bin | 10100111100011010… |
… | …10001001100001001 |
3 | 1002000121222012111101 |
4 | 22132031101030021 |
5 | 141012004304001 |
6 | 5055430301401 |
7 | 545433143050 |
oct | 123615211411 |
9 | 32017865441 |
10 | 11244213001 |
11 | 485007971a |
12 | 22197b7861 |
13 | 10a26c1c98 |
14 | 7894c1397 |
15 | 45c22da01 |
hex | 29e351309 |
11244213001 has 4 divisors (see below), whose sum is σ = 12850529152. Its totient is φ = 9637896852.
The previous prime is 11244212989. The next prime is 11244213011. The reversal of 11244213001 is 10031244211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11244213001 - 221 = 11242115849 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11244213001.
It is not an unprimeable number, because it can be changed into a prime (11244213011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 803158065 + ... + 803158078.
It is an arithmetic number, because the mean of its divisors is an integer number (3212632288).
Almost surely, 211244213001 is an apocalyptic number.
It is an amenable number.
11244213001 is a deficient number, since it is larger than the sum of its proper divisors (1606316151).
11244213001 is an equidigital number, since it uses as much as digits as its factorization.
11244213001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1606316150.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 11244213001 its reverse (10031244211), we get a palindrome (21275457212).
The spelling of 11244213001 in words is "eleven billion, two hundred forty-four million, two hundred thirteen thousand, one".
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