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1124430111241 = 2329148277451
BaseRepresentation
bin10000010111001101010…
…000011110001000001001
310222111100110122000010121
4100113031100132020021
5121410313102024431
62220320035343241
7144144266150443
oct20271520361011
93874313560117
101124430111241
113a3960536178
12161b09451b21
13820582296b8
143c5cbca5493
151e3b0602611
hex105cd41e209

1124430111241 has 4 divisors (see below), whose sum is σ = 1124478411984. Its totient is φ = 1124381810500.

The previous prime is 1124430111227. The next prime is 1124430111271. The reversal of 1124430111241 is 1421110344211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1124430111241 - 25 = 1124430111209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1124430111221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24115435 + ... + 24162016.

It is an arithmetic number, because the mean of its divisors is an integer number (281119602996).

Almost surely, 21124430111241 is an apocalyptic number.

It is an amenable number.

1124430111241 is a deficient number, since it is larger than the sum of its proper divisors (48300743).

1124430111241 is an equidigital number, since it uses as much as digits as its factorization.

1124430111241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48300742.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 1124430111241 its reverse (1421110344211), we get a palindrome (2545540455452).

The spelling of 1124430111241 in words is "one trillion, one hundred twenty-four billion, four hundred thirty million, one hundred eleven thousand, two hundred forty-one".

Divisors: 1 23291 48277451 1124430111241