Base | Representation |
---|---|
bin | 10000010111001101111… |
… | …011010100010110101001 |
3 | 10222111101020202122202112 |
4 | 100113031323110112221 |
5 | 121410323440442101 |
6 | 2220321120212105 |
7 | 144144463501325 |
oct | 20271573242651 |
9 | 3874336678675 |
10 | 1124441343401 |
11 | 3a3966908052 |
12 | 161b1116a035 |
13 | 8205a66004c |
14 | 3c5cd58a985 |
15 | 1e3b15c06bb |
hex | 105cded45a9 |
1124441343401 has 2 divisors, whose sum is σ = 1124441343402. Its totient is φ = 1124441343400.
The previous prime is 1124441343299. The next prime is 1124441343419. The reversal of 1124441343401 is 1043431444211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1116718449001 + 7722894400 = 1056749^2 + 87880^2 .
It is a cyclic number.
It is not a de Polignac number, because 1124441343401 - 222 = 1124437149097 is a prime.
It is not a weakly prime, because it can be changed into another prime (1124441343601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562220671700 + 562220671701.
It is an arithmetic number, because the mean of its divisors is an integer number (562220671701).
Almost surely, 21124441343401 is an apocalyptic number.
It is an amenable number.
1124441343401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1124441343401 is an equidigital number, since it uses as much as digits as its factorization.
1124441343401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 1124441343401 its reverse (1043431444211), we get a palindrome (2167872787612).
The spelling of 1124441343401 in words is "one trillion, one hundred twenty-four billion, four hundred forty-one million, three hundred forty-three thousand, four hundred one".
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