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11253404153 = 103109256351
BaseRepresentation
bin10100111101100000…
…10101000111111001
31002001021021011101102
422132300111013321
5141021332413103
65100355301145
7545604233315
oct123660250771
932037234342
1011253404153
114855287112
1222208aa7b5
1310a458c634
1478a7d4b45
1545ce46e88
hex29ec151f9

11253404153 has 4 divisors (see below), whose sum is σ = 11362660608. Its totient is φ = 11144147700.

The previous prime is 11253404137. The next prime is 11253404177. The reversal of 11253404153 is 35140435211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11253404153 - 24 = 11253404137 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11253404653) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54628073 + ... + 54628278.

It is an arithmetic number, because the mean of its divisors is an integer number (2840665152).

Almost surely, 211253404153 is an apocalyptic number.

It is an amenable number.

11253404153 is a deficient number, since it is larger than the sum of its proper divisors (109256455).

11253404153 is a wasteful number, since it uses less digits than its factorization.

11253404153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109256454.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 11253404153 its reverse (35140435211), we get a palindrome (46393839364).

The spelling of 11253404153 in words is "eleven billion, two hundred fifty-three million, four hundred four thousand, one hundred fifty-three".

Divisors: 1 103 109256351 11253404153