112540101433 has 2 divisors, whose sum is σ = 112540101434. Its totient is φ = 112540101432.

The previous prime is 112540101403. The next prime is 112540101461. The reversal of 112540101433 is 334101045211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65038770729 + 47501330704 = 255027^2 + 217948^2 .

It is an emirp because it is prime and its reverse (334101045211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112540101433 - 2¹³ = 112540093241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112540101398 and 112540101407.

It is not a weakly prime, because it can be changed into another prime (112540101403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56270050716 + 56270050717.

It is an arithmetic number, because the mean of its divisors is an integer number (56270050717).

Almost surely, 2^112540101433 is an apocalyptic number.

It is an amenable number.

112540101433 is a deficient number, since it is larger than the sum of its proper divisors (1).

112540101433 is an equidigital number, since it uses as much as digits as its factorization.

112540101433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 112540101433 its reverse (334101045211), we get a palindrome (446641146644).

The spelling of 112540101433 in words is "one hundred twelve billion, five hundred forty million, one hundred one thousand, four hundred thirty-three".