Base | Representation |
---|---|
bin | 10100111101100110… |
… | …11100010101010001 |
3 | 1002001022210121200011 |
4 | 22132303130111101 |
5 | 141022040020423 |
6 | 5100424554521 |
7 | 545614202233 |
oct | 123663342521 |
9 | 32038717604 |
10 | 11254220113 |
11 | 4855794164 |
12 | 2221022a41 |
13 | 10a47b6b56 |
14 | 78a968253 |
15 | 45d058b0d |
hex | 29ecdc551 |
11254220113 has 2 divisors, whose sum is σ = 11254220114. Its totient is φ = 11254220112.
The previous prime is 11254220063. The next prime is 11254220123. The reversal of 11254220113 is 31102245211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8012398144 + 3241821969 = 89512^2 + 56937^2 .
It is an emirp because it is prime and its reverse (31102245211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11254220113 - 233 = 2664285521 is a prime.
It is not a weakly prime, because it can be changed into another prime (11254220123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5627110056 + 5627110057.
It is an arithmetic number, because the mean of its divisors is an integer number (5627110057).
Almost surely, 211254220113 is an apocalyptic number.
It is an amenable number.
11254220113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11254220113 is an equidigital number, since it uses as much as digits as its factorization.
11254220113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 11254220113 its reverse (31102245211), we get a palindrome (42356465324).
The spelling of 11254220113 in words is "eleven billion, two hundred fifty-four million, two hundred twenty thousand, one hundred thirteen".
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