Base | Representation |
---|---|
bin | 10000011000001001000… |
… | …010101001111010010001 |
3 | 10222120221100222020211212 |
4 | 100120021002221322101 |
5 | 121414341334404244 |
6 | 2221003345345505 |
7 | 144211165462406 |
oct | 20301102517221 |
9 | 3876840866755 |
10 | 1125433122449 |
11 | 3a4325726359 |
12 | 162149338295 |
13 | 82187c7c35c |
14 | 3c6851982ad |
15 | 1e41d6cad9e |
hex | 106090a9e91 |
1125433122449 has 2 divisors, whose sum is σ = 1125433122450. Its totient is φ = 1125433122448.
The previous prime is 1125433122403. The next prime is 1125433122467. The reversal of 1125433122449 is 9442213345211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1058542611025 + 66890511424 = 1028855^2 + 258632^2 .
It is an emirp because it is prime and its reverse (9442213345211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1125433122449 - 28 = 1125433122193 is a prime.
It is not a weakly prime, because it can be changed into another prime (1125433122949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562716561224 + 562716561225.
It is an arithmetic number, because the mean of its divisors is an integer number (562716561225).
Almost surely, 21125433122449 is an apocalyptic number.
It is an amenable number.
1125433122449 is a deficient number, since it is larger than the sum of its proper divisors (1).
1125433122449 is an equidigital number, since it uses as much as digits as its factorization.
1125433122449 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 207360, while the sum is 41.
The spelling of 1125433122449 in words is "one trillion, one hundred twenty-five billion, four hundred thirty-three million, one hundred twenty-two thousand, four hundred forty-nine".
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