Base | Representation |
---|---|
bin | 10100111101101111… |
… | …01011100100101010 |
3 | 1002001101220001200100 |
4 | 22132313223210222 |
5 | 141022331043424 |
6 | 5100504450230 |
7 | 545626510266 |
oct | 123667534452 |
9 | 32041801610 |
10 | 11255331114 |
11 | 4856382945 |
12 | 2221479976 |
13 | 10a4ab5751 |
14 | 78ab770a6 |
15 | 45d1c7dc9 |
hex | 29edeb92a |
11255331114 has 96 divisors (see below), whose sum is σ = 26060233680. Its totient is φ = 3504743424.
The previous prime is 11255331103. The next prime is 11255331119. The reversal of 11255331114 is 41113355211.
11255331114 is a `hidden beast` number, since 1 + 12 + 5 + 533 + 1 + 114 = 666.
It can be written as a sum of positive squares in 8 ways, for example, as 4204874025 + 7050457089 = 64845^2 + 83967^2 .
It is not an unprimeable number, because it can be changed into a prime (11255331119) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2016832 + ... + 2022404.
Almost surely, 211255331114 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11255331114, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13030116840).
11255331114 is an abundant number, since it is smaller than the sum of its proper divisors (14804902566).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11255331114 is a wasteful number, since it uses less digits than its factorization.
11255331114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5736 (or 5733 counting only the distinct ones).
The product of its digits is 1800, while the sum is 27.
Adding to 11255331114 its reverse (41113355211), we get a palindrome (52368686325).
The spelling of 11255331114 in words is "eleven billion, two hundred fifty-five million, three hundred thirty-one thousand, one hundred fourteen".
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