Base | Representation |
---|---|
bin | 10100111101101111… |
… | …01011100100011111 |
3 | 1002001101220001122221 |
4 | 22132313223210133 |
5 | 141022331043403 |
6 | 5100504450211 |
7 | 545626510252 |
oct | 123667534437 |
9 | 32041801587 |
10 | 11255331103 |
11 | 4856382935 |
12 | 2221479967 |
13 | 10a4ab5743 |
14 | 78ab77099 |
15 | 45d1c7dbd |
hex | 29edeb91f |
11255331103 has 2 divisors, whose sum is σ = 11255331104. Its totient is φ = 11255331102.
The previous prime is 11255331097. The next prime is 11255331119. The reversal of 11255331103 is 30113355211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11255331103 - 25 = 11255331071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11255331133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5627665551 + 5627665552.
It is an arithmetic number, because the mean of its divisors is an integer number (5627665552).
Almost surely, 211255331103 is an apocalyptic number.
11255331103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11255331103 is an equidigital number, since it uses as much as digits as its factorization.
11255331103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1350, while the sum is 25.
Adding to 11255331103 its reverse (30113355211), we get a palindrome (41368686314).
The spelling of 11255331103 in words is "eleven billion, two hundred fifty-five million, three hundred thirty-one thousand, one hundred three".
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