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112601501347 is a prime number
BaseRepresentation
bin110100011011110010…
…0101000111010100011
3101202122101120221022211
41220313210220322203
53321101441020342
6123421200542551
711064240653326
oct1506744507243
9352571527284
10112601501347
1143832680625
12199a6021a57
13a80647730a
1456428d67bd
152de06c2c17
hex1a37928ea3

112601501347 has 2 divisors, whose sum is σ = 112601501348. Its totient is φ = 112601501346.

The previous prime is 112601501317. The next prime is 112601501399. The reversal of 112601501347 is 743105106211.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 112601501347 - 215 = 112601468579 is a prime.

It is a super-3 number, since 3×1126015013473 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (112601501317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56300750673 + 56300750674.

It is an arithmetic number, because the mean of its divisors is an integer number (56300750674).

Almost surely, 2112601501347 is an apocalyptic number.

112601501347 is a deficient number, since it is larger than the sum of its proper divisors (1).

112601501347 is an equidigital number, since it uses as much as digits as its factorization.

112601501347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 31.

Adding to 112601501347 its reverse (743105106211), we get a palindrome (855706607558).

The spelling of 112601501347 in words is "one hundred twelve billion, six hundred one million, five hundred one thousand, three hundred forty-seven".