Base | Representation |
---|---|
bin | 11001100111111111100100… |
… | …001100100011001111010011 |
3 | 112210000222001012201022200201 |
4 | 121213333210030203033103 |
5 | 104232432011144000214 |
6 | 1035405231345400031 |
7 | 32511161026563436 |
oct | 3147774414431723 |
9 | 483028035638621 |
10 | 112699475375059 |
11 | 32a00640864141 |
12 | 10781ab6339017 |
13 | 4ab66903a80b1 |
14 | 1db898016d81d |
15 | d0688a6b8274 |
hex | 667fe43233d3 |
112699475375059 has 2 divisors, whose sum is σ = 112699475375060. Its totient is φ = 112699475375058.
The previous prime is 112699475375027. The next prime is 112699475375099. The reversal of 112699475375059 is 950573574996211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112699475375059 - 25 = 112699475375027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112699475374982 and 112699475375000.
It is not a weakly prime, because it can be changed into another prime (112699475375099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56349737687529 + 56349737687530.
It is an arithmetic number, because the mean of its divisors is an integer number (56349737687530).
Almost surely, 2112699475375059 is an apocalyptic number.
112699475375059 is a deficient number, since it is larger than the sum of its proper divisors (1).
112699475375059 is an equidigital number, since it uses as much as digits as its factorization.
112699475375059 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 642978000, while the sum is 73.
The spelling of 112699475375059 in words is "one hundred twelve trillion, six hundred ninety-nine billion, four hundred seventy-five million, three hundred seventy-five thousand, fifty-nine".
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