Base | Representation |
---|---|
bin | 11001101011000000101011… |
… | …100111011001011010000001 |
3 | 112210202210021020211120000111 |
4 | 121223000223213121122001 |
5 | 104244331142444301332 |
6 | 1040044403234151321 |
7 | 32532151360202206 |
oct | 3153005347313201 |
9 | 483683236746014 |
10 | 112906832025217 |
11 | 32a805782264aa |
12 | 107b6125722541 |
13 | 4b000b78742a9 |
14 | 1dc4a112c9cad |
15 | d0be74905947 |
hex | 66b02b9d9681 |
112906832025217 has 2 divisors, whose sum is σ = 112906832025218. Its totient is φ = 112906832025216.
The previous prime is 112906832025209. The next prime is 112906832025277. The reversal of 112906832025217 is 712520238609211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 112819576182336 + 87255842881 = 10621656^2 + 295391^2 .
It is a cyclic number.
It is not a de Polignac number, because 112906832025217 - 23 = 112906832025209 is a prime.
It is not a weakly prime, because it can be changed into another prime (112906832025277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56453416012608 + 56453416012609.
It is an arithmetic number, because the mean of its divisors is an integer number (56453416012609).
Almost surely, 2112906832025217 is an apocalyptic number.
It is an amenable number.
112906832025217 is a deficient number, since it is larger than the sum of its proper divisors (1).
112906832025217 is an equidigital number, since it uses as much as digits as its factorization.
112906832025217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760, while the sum is 49.
The spelling of 112906832025217 in words is "one hundred twelve trillion, nine hundred six billion, eight hundred thirty-two million, twenty-five thousand, two hundred seventeen".
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