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112911094753 is a prime number
BaseRepresentation
bin110100100101000000…
…1101001001111100001
3101210102222010220122021
41221022001221033201
53322220220013003
6123512020341441
711105020320112
oct1511201511741
9353388126567
10112911094753
1143981407746
1219a71844881
13a855653892
145671a86209
152e0c9792bd
hex1a4a0693e1

112911094753 has 2 divisors, whose sum is σ = 112911094754. Its totient is φ = 112911094752.

The previous prime is 112911094729. The next prime is 112911094859. The reversal of 112911094753 is 357490119211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111834729889 + 1076364864 = 334417^2 + 32808^2 .

It is an emirp because it is prime and its reverse (357490119211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112911094753 is a prime.

It is a super-3 number, since 3×1129110947533 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (112911091753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56455547376 + 56455547377.

It is an arithmetic number, because the mean of its divisors is an integer number (56455547377).

Almost surely, 2112911094753 is an apocalyptic number.

It is an amenable number.

112911094753 is a deficient number, since it is larger than the sum of its proper divisors (1).

112911094753 is an equidigital number, since it uses as much as digits as its factorization.

112911094753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 68040, while the sum is 43.

The spelling of 112911094753 in words is "one hundred twelve billion, nine hundred eleven million, ninety-four thousand, seven hundred fifty-three".