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11299433 = 19976131
BaseRepresentation
bin101011000110…
…101001101001
3210021001220112
4223012221221
510343040213
61042104105
7165020645
oct53065151
923231815
1011299433
116418482
12394b035
132458172
141701c25
15ed2ea8
hexac6a69

11299433 has 8 divisors (see below), whose sum is σ = 12018720. Its totient is φ = 10592640.

The previous prime is 11299403. The next prime is 11299459. The reversal of 11299433 is 33499211.

11299433 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11299433 - 210 = 11298409 is a prime.

It is a super-2 number, since 2×112994332 = 255354372242978, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11299433.

It is not an unprimeable number, because it can be changed into a prime (11299403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1223 + ... + 4908.

It is an arithmetic number, because the mean of its divisors is an integer number (1502340).

Almost surely, 211299433 is an apocalyptic number.

It is an amenable number.

11299433 is a deficient number, since it is larger than the sum of its proper divisors (719287).

11299433 is an equidigital number, since it uses as much as digits as its factorization.

11299433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6247.

The product of its digits is 5832, while the sum is 32.

The square root of 11299433 is about 3361.4629255727. The cubic root of 11299433 is about 224.3979493290.

The spelling of 11299433 in words is "eleven million, two hundred ninety-nine thousand, four hundred thirty-three".

Divisors: 1 19 97 1843 6131 116489 594707 11299433