Base | Representation |
---|---|
bin | 11001101100010111011111… |
… | …011100100111011110010011 |
3 | 112211002200212022111120201212 |
4 | 121230113133130213132103 |
5 | 104302343042103130342 |
6 | 1040155300413450335 |
7 | 32541661263000431 |
oct | 3154273734473623 |
9 | 484080768446655 |
10 | 113000043411347 |
11 | 3300705a667514 |
12 | 108101b9aa09ab |
13 | 4b08b20ac0841 |
14 | 1dc93348d7d51 |
15 | d0e5ccb7e182 |
hex | 66c5df727793 |
113000043411347 has 2 divisors, whose sum is σ = 113000043411348. Its totient is φ = 113000043411346.
The previous prime is 113000043411293. The next prime is 113000043411361. The reversal of 113000043411347 is 743114340000311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113000043411347 - 234 = 112982863542163 is a prime.
It is not a weakly prime, because it can be changed into another prime (113000043410347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56500021705673 + 56500021705674.
It is an arithmetic number, because the mean of its divisors is an integer number (56500021705674).
Almost surely, 2113000043411347 is an apocalyptic number.
113000043411347 is a deficient number, since it is larger than the sum of its proper divisors (1).
113000043411347 is an equidigital number, since it uses as much as digits as its factorization.
113000043411347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 113000043411347 its reverse (743114340000311), we get a palindrome (856114383411658).
The spelling of 113000043411347 in words is "one hundred thirteen trillion, forty-three million, four hundred eleven thousand, three hundred forty-seven".
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