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11300028135169 is a prime number
BaseRepresentation
bin1010010001101111111000…
…1010011011011100000001
31111000021100101112010020211
42210123332022123130001
52440114424200311134
640011054455434121
72244254142226504
oct244337612333401
944007311463224
1011300028135169
113667351322614
121326030685941
1363c785023b97
142b0cd231d13b
15148e16574764
hexa46fe29b701

11300028135169 has 2 divisors, whose sum is σ = 11300028135170. Its totient is φ = 11300028135168.

The previous prime is 11300028135101. The next prime is 11300028135199. The reversal of 11300028135169 is 96153182000311.

11300028135169 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7039003284544 + 4261024850625 = 2653112^2 + 2064225^2 .

It is a cyclic number.

It is not a de Polignac number, because 11300028135169 - 29 = 11300028134657 is a prime.

It is a super-3 number, since 3×113000281351693 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (11300028135199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650014067584 + 5650014067585.

It is an arithmetic number, because the mean of its divisors is an integer number (5650014067585).

Almost surely, 211300028135169 is an apocalyptic number.

It is an amenable number.

11300028135169 is a deficient number, since it is larger than the sum of its proper divisors (1).

11300028135169 is an equidigital number, since it uses as much as digits as its factorization.

11300028135169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 40.

The spelling of 11300028135169 in words is "eleven trillion, three hundred billion, twenty-eight million, one hundred thirty-five thousand, one hundred sixty-nine".