Base | Representation |
---|---|
bin | 10101000011000101… |
… | …00000001111011011 |
3 | 1002011112011010120121 |
4 | 22201202200033123 |
5 | 141120312030243 |
6 | 5105144334111 |
7 | 550012234654 |
oct | 124142401733 |
9 | 32145133517 |
10 | 11300111323 |
11 | 4879688986 |
12 | 2234474337 |
13 | 10b1164007 |
14 | 792ab252b |
15 | 4620c11ed |
hex | 2a18a03db |
11300111323 has 2 divisors, whose sum is σ = 11300111324. Its totient is φ = 11300111322.
The previous prime is 11300111299. The next prime is 11300111359. The reversal of 11300111323 is 32311100311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11300111323 - 221 = 11298014171 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11300111297 and 11300111306.
It is not a weakly prime, because it can be changed into another prime (11300111023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650055661 + 5650055662.
It is an arithmetic number, because the mean of its divisors is an integer number (5650055662).
Almost surely, 211300111323 is an apocalyptic number.
11300111323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300111323 is an equidigital number, since it uses as much as digits as its factorization.
11300111323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11300111323 its reverse (32311100311), we get a palindrome (43611211634).
The spelling of 11300111323 in words is "eleven billion, three hundred million, one hundred eleven thousand, three hundred twenty-three".
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