Base | Representation |
---|---|
bin | 10000011100011001111… |
… | …110111000011010101001 |
3 | 11000000202111112020201102 |
4 | 100130121332320122221 |
5 | 122003231123011012 |
6 | 2223042005331145 |
7 | 144432521116052 |
oct | 20343176703251 |
9 | 4000674466642 |
10 | 1130012313257 |
11 | 3a6265545173 |
12 | 163006a06ab5 |
13 | 82737891b09 |
14 | 3c99b3d9729 |
15 | 1e5da70d2c2 |
hex | 10719fb86a9 |
1130012313257 has 2 divisors, whose sum is σ = 1130012313258. Its totient is φ = 1130012313256.
The previous prime is 1130012313251. The next prime is 1130012313323. The reversal of 1130012313257 is 7523132100311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1121091321856 + 8920991401 = 1058816^2 + 94451^2 .
It is a cyclic number.
It is not a de Polignac number, because 1130012313257 - 214 = 1130012296873 is a prime.
It is a super-2 number, since 2×11300123132572 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1130012313251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565006156628 + 565006156629.
It is an arithmetic number, because the mean of its divisors is an integer number (565006156629).
Almost surely, 21130012313257 is an apocalyptic number.
It is an amenable number.
1130012313257 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130012313257 is an equidigital number, since it uses as much as digits as its factorization.
1130012313257 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3780, while the sum is 29.
Adding to 1130012313257 its reverse (7523132100311), we get a palindrome (8653144413568).
The spelling of 1130012313257 in words is "one trillion, one hundred thirty billion, twelve million, three hundred thirteen thousand, two hundred fifty-seven".
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