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113001433 is a prime number
BaseRepresentation
bin1101011110001…
…00001111011001
321212122001211021
412233010033121
5212412021213
615114002441
72541332146
oct657041731
9255561737
10113001433
1158871716
1231a16421
131a54656c
14110173cd
159dc1d8d
hex6bc43d9

113001433 has 2 divisors, whose sum is σ = 113001434. Its totient is φ = 113001432.

The previous prime is 113001409. The next prime is 113001437. The reversal of 113001433 is 334100311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109998144 + 3003289 = 10488^2 + 1733^2 .

It is a cyclic number.

It is not a de Polignac number, because 113001433 - 213 = 112993241 is a prime.

It is not a weakly prime, because it can be changed into another prime (113001437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56500716 + 56500717.

It is an arithmetic number, because the mean of its divisors is an integer number (56500717).

Almost surely, 2113001433 is an apocalyptic number.

It is an amenable number.

113001433 is a deficient number, since it is larger than the sum of its proper divisors (1).

113001433 is an equidigital number, since it uses as much as digits as its factorization.

113001433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 113001433 is about 10630.2132151712. The cubic root of 113001433 is about 483.4608563500.

Adding to 113001433 its reverse (334100311), we get a palindrome (447101744).

The spelling of 113001433 in words is "one hundred thirteen million, one thousand, four hundred thirty-three".