Base | Representation |
---|---|
bin | 10101000011000101… |
… | …11010110010101001 |
3 | 1002011112100122202101 |
4 | 22201202322302221 |
5 | 141120324020243 |
6 | 5105150533401 |
7 | 550013200012 |
oct | 124142726251 |
9 | 32145318671 |
10 | 11300220073 |
11 | 487975265a |
12 | 2234507261 |
13 | 10b11a166c |
14 | 792b00009 |
15 | 4620e354d |
hex | 2a18baca9 |
11300220073 has 2 divisors, whose sum is σ = 11300220074. Its totient is φ = 11300220072.
The previous prime is 11300220017. The next prime is 11300220077. The reversal of 11300220073 is 37002200311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10933420969 + 366799104 = 104563^2 + 19152^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11300220073 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11300220073.
It is not a weakly prime, because it can be changed into another prime (11300220077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650110036 + 5650110037.
It is an arithmetic number, because the mean of its divisors is an integer number (5650110037).
Almost surely, 211300220073 is an apocalyptic number.
It is an amenable number.
11300220073 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300220073 is an equidigital number, since it uses as much as digits as its factorization.
11300220073 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 19.
Adding to 11300220073 its reverse (37002200311), we get a palindrome (48302420384).
The spelling of 11300220073 in words is "eleven billion, three hundred million, two hundred twenty thousand, seventy-three".
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