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11300220073 is a prime number
BaseRepresentation
bin10101000011000101…
…11010110010101001
31002011112100122202101
422201202322302221
5141120324020243
65105150533401
7550013200012
oct124142726251
932145318671
1011300220073
11487975265a
122234507261
1310b11a166c
14792b00009
154620e354d
hex2a18baca9

11300220073 has 2 divisors, whose sum is σ = 11300220074. Its totient is φ = 11300220072.

The previous prime is 11300220017. The next prime is 11300220077. The reversal of 11300220073 is 37002200311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10933420969 + 366799104 = 104563^2 + 19152^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11300220073 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11300220073.

It is not a weakly prime, because it can be changed into another prime (11300220077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650110036 + 5650110037.

It is an arithmetic number, because the mean of its divisors is an integer number (5650110037).

Almost surely, 211300220073 is an apocalyptic number.

It is an amenable number.

11300220073 is a deficient number, since it is larger than the sum of its proper divisors (1).

11300220073 is an equidigital number, since it uses as much as digits as its factorization.

11300220073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 19.

Adding to 11300220073 its reverse (37002200311), we get a palindrome (48302420384).

The spelling of 11300220073 in words is "eleven billion, three hundred million, two hundred twenty thousand, seventy-three".