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113002313001 = 337667437667
BaseRepresentation
bin110100100111101110…
…1100111010100101001
3101210200022210021112220
41221033131213110221
53322412043004001
6123525035424253
711110205545404
oct1511735472451
9353608707486
10113002313001
1143a18950326
1219a982b5089
13a86b511186
14567dc2cd3b
152e15996c36
hex1a4f767529

113002313001 has 4 divisors (see below), whose sum is σ = 150669750672. Its totient is φ = 75334875332.

The previous prime is 113002312961. The next prime is 113002313069. The reversal of 113002313001 is 100313200311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113002313001 - 27 = 113002312873 is a prime.

It is not an unprimeable number, because it can be changed into a prime (113002313071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18833718831 + ... + 18833718836.

It is an arithmetic number, because the mean of its divisors is an integer number (37667437668).

Almost surely, 2113002313001 is an apocalyptic number.

It is an amenable number.

113002313001 is a deficient number, since it is larger than the sum of its proper divisors (37667437671).

113002313001 is an equidigital number, since it uses as much as digits as its factorization.

113002313001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37667437670.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 113002313001 its reverse (100313200311), we get a palindrome (213315513312).

The spelling of 113002313001 in words is "one hundred thirteen billion, two million, three hundred thirteen thousand, one".

Divisors: 1 3 37667437667 113002313001