113002424434331 has 4 divisors (see below), whose sum is σ = 113007855436272. Its totient is φ = 112996993432392.

The previous prime is 113002424434271. The next prime is 113002424434343. The reversal of 113002424434331 is 133434424200311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113002424434331 - 2¹⁰ = 113002424433307 is a prime.

It is a super-2 number, since 2×113002424434331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113002424434291 and 113002424434300.

It is not an unprimeable number, because it can be changed into a prime (113002424434351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2715469760 + ... + 2715511373.

It is an arithmetic number, because the mean of its divisors is an integer number (28251963859068).

Almost surely, 2^{113002424434331} is an apocalyptic number.

113002424434331 is a deficient number, since it is larger than the sum of its proper divisors (5431001941).

113002424434331 is an equidigital number, since it uses as much as digits as its factorization.

113002424434331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5431001940.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 113002424434331 its reverse (133434424200311), we get a palindrome (246436848634642).

The spelling of 113002424434331 in words is "one hundred thirteen trillion, two billion, four hundred twenty-four million, four hundred thirty-four thousand, three hundred thirty-one".