Base | Representation |
---|---|
bin | 110100100111101111… |
… | …0000110111000000011 |
3 | 101210200100000211211122 |
4 | 1221033132012320003 |
5 | 3322412111122433 |
6 | 123525042302455 |
7 | 11110206624245 |
oct | 1511736067003 |
9 | 353610024748 |
10 | 113002442243 |
11 | 43a18a29439 |
12 | 19a98357a2b |
13 | a86b557c52 |
14 | 567dc64095 |
15 | 2e159c0198 |
hex | 1a4f786e03 |
113002442243 has 4 divisors (see below), whose sum is σ = 113006957160. Its totient is φ = 112997927328.
The previous prime is 113002442213. The next prime is 113002442299. The reversal of 113002442243 is 342244200311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113002442243 - 210 = 113002441219 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113002442213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2219705 + ... + 2270042.
It is an arithmetic number, because the mean of its divisors is an integer number (28251739290).
Almost surely, 2113002442243 is an apocalyptic number.
113002442243 is a deficient number, since it is larger than the sum of its proper divisors (4514917).
113002442243 is an equidigital number, since it uses as much as digits as its factorization.
113002442243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4514916.
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 113002442243 its reverse (342244200311), we get a palindrome (455246642554).
The spelling of 113002442243 in words is "one hundred thirteen billion, two million, four hundred forty-two thousand, two hundred forty-three".
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