11300311331233 has 2 divisors, whose sum is σ = 11300311331234. Its totient is φ = 11300311331232.

The previous prime is 11300311331171. The next prime is 11300311331237. The reversal of 11300311331233 is 33213311300311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10432073136384 + 868238194849 = 3229872^2 + 931793^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11300311331233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11300311331198 and 11300311331207.

It is not a weakly prime, because it can be changed into another prime (11300311331237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650155665616 + 5650155665617.

It is an arithmetic number, because the mean of its divisors is an integer number (5650155665617).

Almost surely, 2^{11300311331233} is an apocalyptic number.

It is an amenable number.

11300311331233 is a deficient number, since it is larger than the sum of its proper divisors (1).

11300311331233 is an equidigital number, since it uses as much as digits as its factorization.

11300311331233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 11300311331233 its reverse (33213311300311), we get a palindrome (44513622631544).

The spelling of 11300311331233 in words is "eleven trillion, three hundred billion, three hundred eleven million, three hundred thirty-one thousand, two hundred thirty-three".