Search a number
-
+
11300330000001 = 37538110952381
BaseRepresentation
bin1010010001110001000000…
…1001111100111010000001
31111000022010102112102221210
42210130100021330322001
52440121033440000001
640011144441440333
72244264466104060
oct244342011747201
944008112472853
1011300330000001
113667496760089
1213260b57a00a9
1363c802725723
142b0d2045a1d7
15148e32d00dd6
hexa471027ce81

11300330000001 has 8 divisors (see below), whose sum is σ = 17219550476224. Its totient is φ = 6457331428560.

The previous prime is 11300329999969. The next prime is 11300330000053. The reversal of 11300330000001 is 10000003300311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11300330000001 - 25 = 11300329999969 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11300330008001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 269055476170 + ... + 269055476211.

It is an arithmetic number, because the mean of its divisors is an integer number (2152443809528).

Almost surely, 211300330000001 is an apocalyptic number.

It is an amenable number.

11300330000001 is a deficient number, since it is larger than the sum of its proper divisors (5919220476223).

11300330000001 is an equidigital number, since it uses as much as digits as its factorization.

11300330000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 538110952391.

The product of its (nonzero) digits is 27, while the sum is 12.

Adding to 11300330000001 its reverse (10000003300311), we get a palindrome (21300333300312).

The spelling of 11300330000001 in words is "eleven trillion, three hundred billion, three hundred thirty million, one", and thus it is an aban number.

Divisors: 1 3 7 21 538110952381 1614332857143 3766776666667 11300330000001