Base | Representation |
---|---|
bin | 100001101011011… |
… | …0011100110110001 |
3 | 2220202101120221102 |
4 | 1003112303212301 |
5 | 4303243131032 |
6 | 304044534145 |
7 | 40001166203 |
oct | 10326634661 |
9 | 2822346842 |
10 | 1130052017 |
11 | 52a980896 |
12 | 276551355 |
13 | 150173543 |
14 | aa122773 |
15 | 69320362 |
hex | 435b39b1 |
1130052017 has 2 divisors, whose sum is σ = 1130052018. Its totient is φ = 1130052016.
The previous prime is 1130051987. The next prime is 1130052029. The reversal of 1130052017 is 7102500311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 918756721 + 211295296 = 30311^2 + 14536^2 .
It is a cyclic number.
It is not a de Polignac number, because 1130052017 - 26 = 1130051953 is a prime.
It is a super-2 number, since 2×11300520172 = 2554035122251536578, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1130052017.
It is not a weakly prime, because it can be changed into another prime (1130052047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565026008 + 565026009.
It is an arithmetic number, because the mean of its divisors is an integer number (565026009).
Almost surely, 21130052017 is an apocalyptic number.
It is an amenable number.
1130052017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130052017 is an equidigital number, since it uses as much as digits as its factorization.
1130052017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 210, while the sum is 20.
The square root of 1130052017 is about 33616.2463252517. The cubic root of 1130052017 is about 1041.5964193297.
Adding to 1130052017 its reverse (7102500311), we get a palindrome (8232552328).
The spelling of 1130052017 in words is "one billion, one hundred thirty million, fifty-two thousand, seventeen".
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