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113010055553 = 317439914951
BaseRepresentation
bin110100100111111101…
…1001001100110000001
3101210200212100122100002
41221033323021212001
53322421033234203
6123525513405345
711110331423423
oct1511773114601
9353625318302
10113010055553
1143a2225942a
1219a9aa09855
13a86ccc2375
145680c86813
152e164c5d88
hex1a4fec9981

113010055553 has 16 divisors (see below), whose sum is σ = 116954038272. Its totient is φ = 109085130000.

The previous prime is 113010055493. The next prime is 113010055573. The reversal of 113010055553 is 355550010311.

It is a cyclic number.

It is not a de Polignac number, because 113010055553 - 220 = 113009006977 is a prime.

It is a super-2 number, since 2×1130100555532 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (113010055573) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22823228 + ... + 22828178.

It is an arithmetic number, because the mean of its divisors is an integer number (7309627392).

Almost surely, 2113010055553 is an apocalyptic number.

It is an amenable number.

113010055553 is a deficient number, since it is larger than the sum of its proper divisors (3943982719).

113010055553 is an equidigital number, since it uses as much as digits as its factorization.

113010055553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6716.

The product of its (nonzero) digits is 5625, while the sum is 29.

Adding to 113010055553 its reverse (355550010311), we get a palindrome (468560065864).

The spelling of 113010055553 in words is "one hundred thirteen billion, ten million, fifty-five thousand, five hundred fifty-three".

Divisors: 1 31 743 991 4951 23033 30721 153481 736313 3678593 4906441 22825703 114036383 152099671 3645485663 113010055553