Base | Representation |
---|---|
bin | 1010010001110011100010… |
… | …1101001100001000011011 |
3 | 1111000100212211200120211121 |
4 | 2210130320231030020123 |
5 | 2440123432120413133 |
6 | 40011340143310111 |
7 | 2244320366554654 |
oct | 244347055141033 |
9 | 44010784616747 |
10 | 11301010326043 |
11 | 3667805792109 |
12 | 13262655ab337 |
13 | 63c8b0666c09 |
14 | 2b0d8695252b |
15 | 148e728d902d |
hex | a4738b4c21b |
11301010326043 has 2 divisors, whose sum is σ = 11301010326044. Its totient is φ = 11301010326042.
The previous prime is 11301010326013. The next prime is 11301010326061. The reversal of 11301010326043 is 34062301010311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11301010326043 - 221 = 11301008228891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11301010325999 and 11301010326017.
It is not a weakly prime, because it can be changed into another prime (11301010326013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650505163021 + 5650505163022.
It is an arithmetic number, because the mean of its divisors is an integer number (5650505163022).
Almost surely, 211301010326043 is an apocalyptic number.
11301010326043 is a deficient number, since it is larger than the sum of its proper divisors (1).
11301010326043 is an equidigital number, since it uses as much as digits as its factorization.
11301010326043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 11301010326043 its reverse (34062301010311), we get a palindrome (45363311336354).
The spelling of 11301010326043 in words is "eleven trillion, three hundred one billion, ten million, three hundred twenty-six thousand, forty-three".
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