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1130101320003 = 33710181092973
BaseRepresentation
bin10000011100011111010…
…010011010100101000011
311000000222201000021000120
4100130133102122211003
5122003421414220003
62223054505151323
7144434651503665
oct20343722324503
94000881007016
101130101320003
113a6300808267
1216303078b543
1382750156926
143c9a9168535
151e5e3440853
hex1071f49a943

1130101320003 has 8 divisors (see below), whose sum is σ = 1547526132048. Its totient is φ = 733038693984.

The previous prime is 1130101319987. The next prime is 1130101320013. The reversal of 1130101320003 is 3000231010311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1130101320003 - 24 = 1130101319987 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1130101320013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5090546376 + ... + 5090546597.

It is an arithmetic number, because the mean of its divisors is an integer number (193440766506).

Almost surely, 21130101320003 is an apocalyptic number.

1130101320003 is a deficient number, since it is larger than the sum of its proper divisors (417424812045).

1130101320003 is a wasteful number, since it uses less digits than its factorization.

1130101320003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10181093013.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1130101320003 its reverse (3000231010311), we get a palindrome (4130332330314).

The spelling of 1130101320003 in words is "one trillion, one hundred thirty billion, one hundred one million, three hundred twenty thousand, three".

Divisors: 1 3 37 111 10181092973 30543278919 376700440001 1130101320003