Base | Representation |
---|---|
bin | 11001101100100001110011… |
… | …101010110111110110011011 |
3 | 112211010202110021021020010021 |
4 | 121230201303222313312123 |
5 | 104303033233222023003 |
6 | 1040204331501531311 |
7 | 32542532623252432 |
oct | 3154416352676633 |
9 | 484122407236107 |
10 | 113011120111003 |
11 | 33010824121954 |
12 | 1081238b573b37 |
13 | 4b09b978912aa |
14 | 1dc9aa5a52119 |
15 | d0ea2a31e2bd |
hex | 66c873ab7d9b |
113011120111003 has 2 divisors, whose sum is σ = 113011120111004. Its totient is φ = 113011120111002.
The previous prime is 113011120110979. The next prime is 113011120111009. The reversal of 113011120111003 is 300111021110311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113011120111003 - 25 = 113011120110971 is a prime.
It is not a weakly prime, because it can be changed into another prime (113011120111009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56505560055501 + 56505560055502.
It is an arithmetic number, because the mean of its divisors is an integer number (56505560055502).
Almost surely, 2113011120111003 is an apocalyptic number.
113011120111003 is a deficient number, since it is larger than the sum of its proper divisors (1).
113011120111003 is an equidigital number, since it uses as much as digits as its factorization.
113011120111003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 16.
Adding to 113011120111003 its reverse (300111021110311), we get a palindrome (413122141221314).
The spelling of 113011120111003 in words is "one hundred thirteen trillion, eleven billion, one hundred twenty million, one hundred eleven thousand, three".
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