Base | Representation |
---|---|
bin | 10000011100011111111… |
… | …111110100111011110001 |
3 | 11000001000112102001211101 |
4 | 100130133333310323301 |
5 | 122003432441140213 |
6 | 2223100012244401 |
7 | 144435154624534 |
oct | 20343777647361 |
9 | 4001015361741 |
10 | 1130113224433 |
11 | 3a63074a9236 |
12 | 163034770701 |
13 | 8275276427b |
14 | 3c9aa986a1b |
15 | 1e5e44e2bdd |
hex | 1071fff4ef1 |
1130113224433 has 2 divisors, whose sum is σ = 1130113224434. Its totient is φ = 1130113224432.
The previous prime is 1130113224367. The next prime is 1130113224553. The reversal of 1130113224433 is 3344223110311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1068188395024 + 61924829409 = 1033532^2 + 248847^2 .
It is a cyclic number.
It is not a de Polignac number, because 1130113224433 - 213 = 1130113216241 is a prime.
It is not a weakly prime, because it can be changed into another prime (1130114224433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565056612216 + 565056612217.
It is an arithmetic number, because the mean of its divisors is an integer number (565056612217).
Almost surely, 21130113224433 is an apocalyptic number.
It is an amenable number.
1130113224433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130113224433 is an equidigital number, since it uses as much as digits as its factorization.
1130113224433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 1130113224433 its reverse (3344223110311), we get a palindrome (4474336334744).
The spelling of 1130113224433 in words is "one trillion, one hundred thirty billion, one hundred thirteen million, two hundred twenty-four thousand, four hundred thirty-three".
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