Base | Representation |
---|---|
bin | 1010010001110100000101… |
… | …0101000011010000000001 |
3 | 1111000101020220220102210201 |
4 | 2210131001111003100001 |
5 | 2440124231134240103 |
6 | 40011402352125201 |
7 | 2244324104323654 |
oct | 244350125032001 |
9 | 44011226812721 |
10 | 11301154993153 |
11 | 366787a411703 |
12 | 13262a5b36801 |
13 | 63c90461965c |
14 | 2b0d9bc4d89b |
15 | 148e8046351d |
hex | a4741543401 |
11301154993153 has 2 divisors, whose sum is σ = 11301154993154. Its totient is φ = 11301154993152.
The previous prime is 11301154993061. The next prime is 11301154993157. The reversal of 11301154993153 is 35139945110311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10187638308864 + 1113516684289 = 3191808^2 + 1055233^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11301154993153 is a prime.
It is a super-2 number, since 2×113011549931532 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11301154993157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650577496576 + 5650577496577.
It is an arithmetic number, because the mean of its divisors is an integer number (5650577496577).
Almost surely, 211301154993153 is an apocalyptic number.
It is an amenable number.
11301154993153 is a deficient number, since it is larger than the sum of its proper divisors (1).
11301154993153 is an equidigital number, since it uses as much as digits as its factorization.
11301154993153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 218700, while the sum is 46.
The spelling of 11301154993153 in words is "eleven trillion, three hundred one billion, one hundred fifty-four million, nine hundred ninety-three thousand, one hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •