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11301154993153 is a prime number
BaseRepresentation
bin1010010001110100000101…
…0101000011010000000001
31111000101020220220102210201
42210131001111003100001
52440124231134240103
640011402352125201
72244324104323654
oct244350125032001
944011226812721
1011301154993153
11366787a411703
1213262a5b36801
1363c90461965c
142b0d9bc4d89b
15148e8046351d
hexa4741543401

11301154993153 has 2 divisors, whose sum is σ = 11301154993154. Its totient is φ = 11301154993152.

The previous prime is 11301154993061. The next prime is 11301154993157. The reversal of 11301154993153 is 35139945110311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10187638308864 + 1113516684289 = 3191808^2 + 1055233^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11301154993153 is a prime.

It is a super-2 number, since 2×113011549931532 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11301154993157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650577496576 + 5650577496577.

It is an arithmetic number, because the mean of its divisors is an integer number (5650577496577).

Almost surely, 211301154993153 is an apocalyptic number.

It is an amenable number.

11301154993153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11301154993153 is an equidigital number, since it uses as much as digits as its factorization.

11301154993153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 218700, while the sum is 46.

The spelling of 11301154993153 in words is "eleven trillion, three hundred one billion, one hundred fifty-four million, nine hundred ninety-three thousand, one hundred fifty-three".