Base | Representation |
---|---|
bin | 11001101100100010111011… |
… | …011100111111000111111011 |
3 | 112211010212120012101222122211 |
4 | 121230202323130333013323 |
5 | 104303043220023232311 |
6 | 1040205051202355551 |
7 | 32542604515640464 |
oct | 3154427334770773 |
9 | 484125505358584 |
10 | 113012324430331 |
11 | 33011291a08887 |
12 | 1081266695bbb7 |
13 | 4b0a02a238791 |
14 | 1dc9b7b987d6b |
15 | d0ea9ae0e821 |
hex | 66c8bb73f1fb |
113012324430331 has 2 divisors, whose sum is σ = 113012324430332. Its totient is φ = 113012324430330.
The previous prime is 113012324430287. The next prime is 113012324430349. The reversal of 113012324430331 is 133034423210311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113012324430331 - 239 = 112462568616443 is a prime.
It is a super-2 number, since 2×1130123244303312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113012324430293 and 113012324430302.
It is not a weakly prime, because it can be changed into another prime (113012324430361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56506162215165 + 56506162215166.
It is an arithmetic number, because the mean of its divisors is an integer number (56506162215166).
Almost surely, 2113012324430331 is an apocalyptic number.
113012324430331 is a deficient number, since it is larger than the sum of its proper divisors (1).
113012324430331 is an equidigital number, since it uses as much as digits as its factorization.
113012324430331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 113012324430331 its reverse (133034423210311), we get a palindrome (246046747640642).
The spelling of 113012324430331 in words is "one hundred thirteen trillion, twelve billion, three hundred twenty-four million, four hundred thirty thousand, three hundred thirty-one".
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