Base | Representation |
---|---|
bin | 10000011100100001000… |
… | …000001101000001100001 |
3 | 11000001001201011110012021 |
4 | 100130201000031001201 |
5 | 122004001301202241 |
6 | 2223101414101441 |
7 | 144435451232425 |
oct | 20344100150141 |
9 | 4001051143167 |
10 | 1130130100321 |
11 | 3a6315a85352 |
12 | 16303a34a881 |
13 | 827560c26c1 |
14 | 3c9accdab85 |
15 | 1e5e5c280d1 |
hex | 1072100d061 |
1130130100321 has 2 divisors, whose sum is σ = 1130130100322. Its totient is φ = 1130130100320.
The previous prime is 1130130100313. The next prime is 1130130100327. The reversal of 1130130100321 is 1230010310311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 666149792400 + 463980307921 = 816180^2 + 681161^2 .
It is a cyclic number.
It is not a de Polignac number, because 1130130100321 - 23 = 1130130100313 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1130130100295 and 1130130100304.
It is not a weakly prime, because it can be changed into another prime (1130130100327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565065050160 + 565065050161.
It is an arithmetic number, because the mean of its divisors is an integer number (565065050161).
Almost surely, 21130130100321 is an apocalyptic number.
It is an amenable number.
1130130100321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130130100321 is an equidigital number, since it uses as much as digits as its factorization.
1130130100321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1130130100321 its reverse (1230010310311), we get a palindrome (2360140410632).
The spelling of 1130130100321 in words is "one trillion, one hundred thirty billion, one hundred thirty million, one hundred thousand, three hundred twenty-one".
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