Base | Representation |
---|---|
bin | 1010010001110111010011… |
… | …1000111010011000000010 |
3 | 1111000110111012121222000121 |
4 | 2210131310320322120002 |
5 | 2440133014112011002 |
6 | 40012024253010454 |
7 | 2244354410122060 |
oct | 244356470723002 |
9 | 44013435558017 |
10 | 11302020032002 |
11 | 3668183735147 |
12 | 13264a7783a2a |
13 | 63ca118c1b6b |
14 | 2b1040aa9030 |
15 | 148ed1386237 |
hex | a4774e3a602 |
11302020032002 has 8 divisors (see below), whose sum is σ = 19374891483456. Its totient is φ = 4843722870852.
The previous prime is 11302020031999. The next prime is 11302020032029. The reversal of 11302020032002 is 20023002020311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 403643572558 + ... + 403643572585.
It is an arithmetic number, because the mean of its divisors is an integer number (2421861435432).
Almost surely, 211302020032002 is an apocalyptic number.
11302020032002 is a deficient number, since it is larger than the sum of its proper divisors (8072871451454).
11302020032002 is an equidigital number, since it uses as much as digits as its factorization.
11302020032002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 807287145152.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 11302020032002 its reverse (20023002020311), we get a palindrome (31325022052313).
The spelling of 11302020032002 in words is "eleven trillion, three hundred two billion, twenty million, thirty-two thousand, two".
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