Base | Representation |
---|---|
bin | 1010010001110111010110… |
… | …0000000101101111100011 |
3 | 1111000110111220221202001112 |
4 | 2210131311200011233203 |
5 | 2440133024224132204 |
6 | 40012025301053535 |
7 | 2244354563325221 |
oct | 244356540055743 |
9 | 44013456852045 |
10 | 11302030302179 |
11 | 366818950a2a1 |
12 | 13264ab0b72ab |
13 | 63ca13a796a6 |
14 | 2b10421bdb11 |
15 | 148ed221426e |
hex | a4775805be3 |
11302030302179 has 2 divisors, whose sum is σ = 11302030302180. Its totient is φ = 11302030302178.
The previous prime is 11302030302103. The next prime is 11302030302197. The reversal of 11302030302179 is 97120303020311.
11302030302179 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with next prime (11302030302197) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11302030302179 - 228 = 11301761866723 is a prime.
It is not a weakly prime, because it can be changed into another prime (11302030302379) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651015151089 + 5651015151090.
It is an arithmetic number, because the mean of its divisors is an integer number (5651015151090).
Almost surely, 211302030302179 is an apocalyptic number.
11302030302179 is a deficient number, since it is larger than the sum of its proper divisors (1).
11302030302179 is an equidigital number, since it uses as much as digits as its factorization.
11302030302179 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 32.
The spelling of 11302030302179 in words is "eleven trillion, three hundred two billion, thirty million, three hundred two thousand, one hundred seventy-nine".
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