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1130203220203 = 7367915339557
BaseRepresentation
bin10000011100100101010…
…111001000100011101011
311000001020210202022211001
4100130211113020203223
5122004124011021303
62223112545215431
7144440326602061
oct20344527104353
94001223668731
101130203220203
113a6353287402
1216305a931577
13827682b42c5
143c9b88d2031
151e5ec36d31d
hex107255c88eb

1130203220203 has 4 divisors (see below), whose sum is σ = 1130218633440. Its totient is φ = 1130187806968.

The previous prime is 1130203220177. The next prime is 1130203220219. The reversal of 1130203220203 is 3020223020311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1130203220203 - 217 = 1130203089131 is a prime.

It is a super-2 number, since 2×11302032202032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1130203224203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7596100 + ... + 7743457.

It is an arithmetic number, because the mean of its divisors is an integer number (282554658360).

Almost surely, 21130203220203 is an apocalyptic number.

1130203220203 is a deficient number, since it is larger than the sum of its proper divisors (15413237).

1130203220203 is an equidigital number, since it uses as much as digits as its factorization.

1130203220203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15413236.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 1130203220203 its reverse (3020223020311), we get a palindrome (4150426240514).

The spelling of 1130203220203 in words is "one trillion, one hundred thirty billion, two hundred three million, two hundred twenty thousand, two hundred three".

Divisors: 1 73679 15339557 1130203220203