1130204023041 has 4 divisors (see below), whose sum is σ = 1506938697392. Its totient is φ = 753469348692.

The previous prime is 1130204023037. The next prime is 1130204023057. The reversal of 1130204023041 is 1403204020311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1130204023041 - 2² = 1130204023037 is a prime.

It is a super-2 number, since 2×1130204023041² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1130204022999 and 1130204023017.

It is not an unprimeable number, because it can be changed into a prime (1130204023031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188367337171 + ... + 188367337176.

It is an arithmetic number, because the mean of its divisors is an integer number (376734674348).

Almost surely, 2^{1130204023041} is an apocalyptic number.

It is an amenable number.

1130204023041 is a deficient number, since it is larger than the sum of its proper divisors (376734674351).

1130204023041 is an equidigital number, since it uses as much as digits as its factorization.

1130204023041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 376734674350.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 1130204023041 its reverse (1403204020311), we get a palindrome (2533408043352).

The spelling of 1130204023041 in words is "one trillion, one hundred thirty billion, two hundred four million, twenty-three thousand, forty-one".