Base | Representation |
---|---|
bin | 10000011100100101110… |
… | …100110111000110111011 |
3 | 11000001021100102020121001 |
4 | 100130211310313012323 |
5 | 122004133004404201 |
6 | 2223113424225431 |
7 | 144440453046541 |
oct | 20344564670673 |
9 | 4001240366531 |
10 | 1130211013051 |
11 | 3a635771a27a |
12 | 16306146b277 |
13 | 82769ab2363 |
14 | 3c9b995dd91 |
15 | 1e5ecdac301 |
hex | 10725d371bb |
1130211013051 has 2 divisors, whose sum is σ = 1130211013052. Its totient is φ = 1130211013050.
The previous prime is 1130211013027. The next prime is 1130211013069. The reversal of 1130211013051 is 1503101120311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1130211013051 - 219 = 1130210488763 is a prime.
It is not a weakly prime, because it can be changed into another prime (1130211013091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565105506525 + 565105506526.
It is an arithmetic number, because the mean of its divisors is an integer number (565105506526).
Almost surely, 21130211013051 is an apocalyptic number.
1130211013051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130211013051 is an equidigital number, since it uses as much as digits as its factorization.
1130211013051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 19.
Adding to 1130211013051 its reverse (1503101120311), we get a palindrome (2633312133362).
The spelling of 1130211013051 in words is "one trillion, one hundred thirty billion, two hundred eleven million, thirteen thousand, fifty-one".
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