11302231131331 has 4 divisors (see below), whose sum is σ = 12916835578672. Its totient is φ = 9687626683992.

The previous prime is 11302231131277. The next prime is 11302231131353. The reversal of 11302231131331 is 13313113220311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11302231131331 - 2¹⁷ = 11302231000259 is a prime.

It is a super-4 number, since 4×11302231131331⁴ (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11302231131296 and 11302231131305.

It is not an unprimeable number, because it can be changed into a prime (11302231131131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 807302223660 + ... + 807302223673.

It is an arithmetic number, because the mean of its divisors is an integer number (3229208894668).

Almost surely, 2^{11302231131331} is an apocalyptic number.

11302231131331 is a deficient number, since it is larger than the sum of its proper divisors (1614604447341).

11302231131331 is an equidigital number, since it uses as much as digits as its factorization.

11302231131331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1614604447340.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11302231131331 its reverse (13313113220311), we get a palindrome (24615344351642).

The spelling of 11302231131331 in words is "eleven trillion, three hundred two billion, two hundred thirty-one million, one hundred thirty-one thousand, three hundred thirty-one".