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113023041403 = 157181719063
BaseRepresentation
bin110100101000010110…
…0101011111101111011
3101210201202210101120111
41221100230223331323
53322432344311103
6123531100005151
711110550000146
oct1512054537573
9353652711514
10113023041403
1143a29618938
1219aa32307b7
13a8728bacbc
1456828a705d
152e176dd86d
hex1a50b2bf7b

113023041403 has 4 divisors (see below), whose sum is σ = 113023917648. Its totient is φ = 113022165160.

The previous prime is 113023041401. The next prime is 113023041421. The reversal of 113023041403 is 304140320311.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 113023041403 - 21 = 113023041401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113023041401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202351 + ... + 516712.

It is an arithmetic number, because the mean of its divisors is an integer number (28255979412).

Almost surely, 2113023041403 is an apocalyptic number.

113023041403 is a deficient number, since it is larger than the sum of its proper divisors (876245).

113023041403 is an equidigital number, since it uses as much as digits as its factorization.

113023041403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 876244.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 113023041403 its reverse (304140320311), we get a palindrome (417163361714).

The spelling of 113023041403 in words is "one hundred thirteen billion, twenty-three million, forty-one thousand, four hundred three".

Divisors: 1 157181 719063 113023041403