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113023123010002 = 256511561505001
BaseRepresentation
bin11001101100101100111111…
…000110010011000111010010
3112211011220102202211200011001
4121230230333012103013102
5104303232323442310002
61040214034513412214
732543436231232162
oct3154547706230722
9484156382750131
10113023123010002
1133015923483597
121081477b26a06a
134b0b05b4cc4aa
141dca4c3bc65a2
15d0eecde63a87
hex66cb3f1931d2

113023123010002 has 4 divisors (see below), whose sum is σ = 169534684515006. Its totient is φ = 56511561505000.

The previous prime is 113023123009999. The next prime is 113023123010041. The reversal of 113023123010002 is 200010321320311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 110171243070001 + 2851879940001 = 10496249^2 + 1688751^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28255780752499 + ... + 28255780752502.

Almost surely, 2113023123010002 is an apocalyptic number.

113023123010002 is a deficient number, since it is larger than the sum of its proper divisors (56511561505004).

113023123010002 is an equidigital number, since it uses as much as digits as its factorization.

113023123010002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56511561505003.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 113023123010002 its reverse (200010321320311), we get a palindrome (313033444330313).

The spelling of 113023123010002 in words is "one hundred thirteen trillion, twenty-three billion, one hundred twenty-three million, ten thousand, two".

Divisors: 1 2 56511561505001 113023123010002