Base | Representation |
---|---|
bin | 1010010001111000100000… |
… | …0101101000011001011101 |
3 | 1111000111022122201101222211 |
4 | 2210132020011220121131 |
5 | 2440134144041231331 |
6 | 40012120240440421 |
7 | 2244365401002040 |
oct | 244361005503135 |
9 | 44014278641884 |
10 | 11302342133341 |
11 | 36683295346a6 |
12 | 1326577619111 |
13 | 63ca6355a67c |
14 | 2b1071792c57 |
15 | 148eee7ad8b1 |
hex | a478816865d |
11302342133341 has 16 divisors (see below), whose sum is σ = 13418376668928. Its totient is φ = 9318317097600.
The previous prime is 11302342133233. The next prime is 11302342133371. The reversal of 11302342133341 is 14333124320311.
It is not a de Polignac number, because 11302342133341 - 215 = 11302342100573 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11302342133371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 277310490 + ... + 277351243.
It is an arithmetic number, because the mean of its divisors is an integer number (838648541808).
Almost surely, 211302342133341 is an apocalyptic number.
It is an amenable number.
11302342133341 is a deficient number, since it is larger than the sum of its proper divisors (2116034535587).
11302342133341 is an equidigital number, since it uses as much as digits as its factorization.
11302342133341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 554661852.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 11302342133341 its reverse (14333124320311), we get a palindrome (25635466453652).
The spelling of 11302342133341 in words is "eleven trillion, three hundred two billion, three hundred forty-two million, one hundred thirty-three thousand, three hundred forty-one".
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