1130242400433 has 12 divisors (see below), whose sum is σ = 1688867955060. Its totient is φ = 727512349536.

The previous prime is 1130242400429. The next prime is 1130242400437. The reversal of 1130242400433 is 3340042420311.

1130242400433 is a `hidden beast` number, since 1 + 13 + 0 + 242 + 400 + 4 + 3 + 3 = 666.

It is an interprime number because it is at equal distance from previous prime (1130242400429) and next prime (1130242400437).

It can be written as a sum of positive squares in 2 ways, for example, as 540330845184 + 589911555249 = 735072^2 + 768057^2 .

It is not a de Polignac number, because 1130242400433 - 2² = 1130242400429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1130242400397 and 1130242400406.

It is not an unprimeable number, because it can be changed into a prime (1130242400437) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2165215066 + ... + 2165215587.

It is an arithmetic number, because the mean of its divisors is an integer number (140738996255).

Almost surely, 2^{1130242400433} is an apocalyptic number.

It is an amenable number.

1130242400433 is a deficient number, since it is larger than the sum of its proper divisors (558625554627).

1130242400433 is a wasteful number, since it uses less digits than its factorization.

1130242400433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4330430688 (or 4330430685 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 1130242400433 its reverse (3340042420311), we get a palindrome (4470284820744).

The spelling of 1130242400433 in words is "one trillion, one hundred thirty billion, two hundred forty-two million, four hundred thousand, four hundred thirty-three".