Base | Representation |
---|---|
bin | 1010010001111010111111… |
… | …1110000010101001011011 |
3 | 1111000120001021202011021111 |
4 | 2210132233332002221123 |
5 | 2440142031333413342 |
6 | 40012310501521151 |
7 | 2244421104153022 |
oct | 244365776025133 |
9 | 44016037664244 |
10 | 11303011232347 |
11 | 366864219868a |
12 | 13267237131b7 |
13 | 63cb3c06a943 |
14 | 2b10d65a58b9 |
15 | 14903d3ca217 |
hex | a47aff82a5b |
11303011232347 has 2 divisors, whose sum is σ = 11303011232348. Its totient is φ = 11303011232346.
The previous prime is 11303011232309. The next prime is 11303011232353. The reversal of 11303011232347 is 74323211030311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11303011232347 - 223 = 11303002843739 is a prime.
It is a super-4 number, since 4×113030112323474 (a number of 53 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (11303011232047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5651505616173 + 5651505616174.
It is an arithmetic number, because the mean of its divisors is an integer number (5651505616174).
Almost surely, 211303011232347 is an apocalyptic number.
11303011232347 is a deficient number, since it is larger than the sum of its proper divisors (1).
11303011232347 is an equidigital number, since it uses as much as digits as its factorization.
11303011232347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 11303011232347 its reverse (74323211030311), we get a palindrome (85626222262658).
The spelling of 11303011232347 in words is "eleven trillion, three hundred three billion, eleven million, two hundred thirty-two thousand, three hundred forty-seven".
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