Base | Representation |
---|---|
bin | 10000011100101011010… |
… | …100111111101101111011 |
3 | 11000001111210010002001011 |
4 | 100130223110333231323 |
5 | 122004330122314003 |
6 | 2223130522534351 |
7 | 144442653503011 |
oct | 20345324775573 |
9 | 4001453102034 |
10 | 1130303323003 |
11 | 3a63a4839098 |
12 | 1630883673b7 |
13 | 82782c6282a |
14 | 3c9c7d0c8b1 |
15 | 1e60604346d |
hex | 1072b53fb7b |
1130303323003 has 4 divisors (see below), whose sum is σ = 1138553712360. Its totient is φ = 1122052933648.
The previous prime is 1130303322991. The next prime is 1130303323021. The reversal of 1130303323003 is 3003233030311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1130303323003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1130303323103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4125194473 + ... + 4125194746.
It is an arithmetic number, because the mean of its divisors is an integer number (284638428090).
Almost surely, 21130303323003 is an apocalyptic number.
1130303323003 is a deficient number, since it is larger than the sum of its proper divisors (8250389357).
1130303323003 is an equidigital number, since it uses as much as digits as its factorization.
1130303323003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8250389356.
The product of its (nonzero) digits is 1458, while the sum is 22.
Adding to 1130303323003 its reverse (3003233030311), we get a palindrome (4133536353314).
The spelling of 1130303323003 in words is "one trillion, one hundred thirty billion, three hundred three million, three hundred twenty-three thousand, three".
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