11303110113 has 4 divisors (see below), whose sum is σ = 15070813488. Its totient is φ = 7535406740.

The previous prime is 11303110009. The next prime is 11303110141. The reversal of 11303110113 is 31101130311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11303110113 - 2¹⁰ = 11303109089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11303110092 and 11303110101.

It is not an unprimeable number, because it can be changed into a prime (11303110153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1883851683 + ... + 1883851688.

It is an arithmetic number, because the mean of its divisors is an integer number (3767703372).

Almost surely, 2^11303110113 is an apocalyptic number.

It is an amenable number.

11303110113 is a deficient number, since it is larger than the sum of its proper divisors (3767703375).

11303110113 is an equidigital number, since it uses as much as digits as its factorization.

11303110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3767703374.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 11303110113 its reverse (31101130311), we get a palindrome (42404240424).

The spelling of 11303110113 in words is "eleven billion, three hundred three million, one hundred ten thousand, one hundred thirteen".